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DOWNLOAD FREE EBOOKS/PDF FOR IITJEE IITJEE is the joint entrance examination conducted for admissions to Indian Institutes of Technology . Cracking this exam requires clarity of thought , sound concepts and good problem solving skills , If you enjoy your studies for two years going through the exam should not be a problem .Have you been searching long for free IIT JEE Preparation books ? Go though the linkIf yes ,you have landed to the right place .I'm providing some of the good books here . All these books are free to download .You can also download the free softwares which are text readers used to open these e-books.pdf - click here.djvu- click here.lit- click
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submitted by Ankit (1727 m) on 25 Apr 2009 11:31:18 IST
Of late many of us have been asking for books or sources to read theory regarding mathematical reasoning. Many of you may have googled it but didn't pay heed to this link :http://www.regentsprep.org/regents/math/math-a.cfmSo compiling it from there . Read it here else the link has been provided . Types of Sentences One of the goals of studying mathematics is to develop the ability to think critically. The study of critical thinking, or reasoning, is called logic. All reasoning is based on the ways we put sentences together. Let's start our examination of l
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write the list of cubes of 1-10 as follows1 12 83 274 645 1256 2167 3438 5129 729revise the last numbersknow pick a perfect cube to check:474552group it by 3 digits, 474 552 see the last digit, &nb
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submitted by Loser! (1000 m) on 30 Sep 2009 21:19:25 IST
This is my first article written on my own. I am doing my 12th in brilliant tutorials.I havent studied anything in 11th due to lack of planning, concentration etc. But i am serious now.I have made a plan basing on last year papers analysis on how to study for JEE in 6 months those who haven’t started their prep till now (I did this for myself and thought of sharing it). First the students need to make their basics clear then they need to follow some standard books by Indian authors meant for JEE than books by foreign authors.I have seen many people asking about the good books for JEE. This is not my personal suggestion but also the suggestion of many students,
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General MethodThe divisor should not be too small. The smallness will giverise to big quotients with several digits. This will lead tocomplications.Another method is to multiply the given number by anothersmall number cubed and find the cube root. Final answer iscalculated by dividing the result by small numberExample 4: Find the cube root of 2We multiply 2 by 53The new Number becomes 2 x 125 = 250Find the cube root of 250 and divide the answer by 5 [since we multiplied the original number by 5Step 1250 : 0 0 0By inspection write down 6 and 34 as the first Q and R .Since 216 is the perfect cube close to 250 and thereminder from 250 is 34.Step 2250 : 0 0 0108 : : 34:
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This is yet another inspiring story which is able to prove that if you have guts and wits then nothing is impossible for you….A guy named Rohit failed his 12th CBSE board exam in 2008.He dropped a year and sat again for IIT JEE and boards unlike others who would only prepare for boards if they fail.He always used to get shouting’s from his parents for letting them down and not studying. He used to study 10 hours a day for JEE and 2 hours for boards.He never bogged down. He kept studying day by day.He answered his boards again and scored 83% .Then after boards he was also going to be tested for IITJEE.Rohit answered JEE 2009 with a cool head
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The JEE 2012 has turned out to be tougher than what most people expected. Most people were expecting it to be easier than 2011, but most agree it was tougher and quite a few even say it was of same level as 2010. The new total of 408 (or should I say 401) has perplexed most pundits. In conclusion, this is wh JEE is such a tough nut to crack - you never know what to expect!
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submitted by sarath (0 m) on 11 May 2012 15:53:56 IST
hey frnds please who has completed 10 th donot get trapped in th words of trhe pro s thy say that the collage is great and it has a nobel history i also got it and i was spoilled a dirty rouge has joined me in nri which is a worst one the faculty who come to the ic bathch and the top 20 batch r good but the other lecturers r worst even in last sections som send jls who has no xperience some of them r inter failed also and ther is also saying that the dean yesu ratnam was arrestd twice for scam and the coordinator ganesh he speaks bad language with students he ia a really worst guy i got 453 marks in ipe 1st year and i was not selectd for ic batch a
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Let the two digit number be xy where x is the tens place digit and y is the ones place digit.Square of a two digit number has a maximum of four digits and minimum of three digits.we know that (x+y)2=x2+2xy+y2also (10x+y)2=100x2+10*2xy+y2Here ones place digit is y^2 tens place digit is 2xy and hundredth place digit is x^2.While calculating the square if there is any remainder it must be added to the next place digit.1. 312ones place digit=12=1tens place digit=2*3*1=6100s place digit=32=9therefore 312=9612. 472ones place digit=72=49=9 &nb
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Here is an Easy way to find Squares of numbers which contain 5 as their last digit..Consider the digits written before 5 as a single number and multiply it be its succcessor and then write it and put 25 as the last two digits of it...For example:to find square of 15:: (1*2)=2 and then write 25 at the end ,ie. 225similarly to find square of 25:: (2*3)=6 and then write 25 at the end i.e, 625for finding square of 105:: (10*11)=110 and then write 25 at the end ,i.e, 11025PLS RATE IT IF YOU LIKE IT !!Some of The Related Articles:What is PSEUDO FORCE ?Image formation in Plane Mirror @ Infinity DistanceKaprekar Transformation for 3-Digit Numbers
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submitted by indiapdu (0 m) on 9 May 2012 15:12:59 IST
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List of Engineering Entrance Exams in India · All India Engineering Entrance Examination(AIEEE) · Amrita Engineering Entrance Examination · AMU Engineering Entrance Exam · Anna University Engineering Entrance Exam ·&nb
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IIT aspirants will now get to see their evaluated JEE answer scripts even before the result is declared on May 18. IIT Delhi, which organised JEE on April 8 this year, has decided to upload the checked optical response sheets of every candidate on the JEE website to maintain transparency and avoid any errors. It is for the first time that the candidates will get a chance to go through their answer sheets to see if they have been evaluated properly. If a candidate finds any discrepancy, he or she can lodge a complaint online. These evaluated answer sheets will be available online from May 5 to May 10. The facility to submit requests for revision will c
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Around 4,80,000 IIT aspirants, who had appeared for the IIT JEE 2012, will be able to view their answer sheets online on the websitesof the respective IITs. The scanned versions of the Optical Response Sheets (ORS) will be displayed on the websites from May 5 to May 10 for candidates to view their answers vis-a-vis the correct responses, including their individual scores. According to GB Reddy, chairman, JEE 2012, the answer key uploaded on the websites will enable students to view the correct answers to all questions versus their answers to each question. They can also register complaints online. "In this process, stude
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Here are the estimated ranks according to my professors: 275+ Top 500255 - 275 500 - 1000230 - 255 1000 - 2000225 - 230 2000 - 2500220 - 225 2500 - 3000210 - 220 3000 - 4000Don't forget JEE was tough this year!
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submitted by smks (0 m) on 8 May 2012 00:26:51 IST
THE MAIN CONCERN WOULD BE OF DROPPERS WHO HAD APPEARED/PASSED IN 12TH IN THE YEAR 20102011 . BECAUSE THE SYSTEM IS CHANGED TO REDUCE THE STRESS FACTOR,AND TO PERFORM BETTER IN THE EXAMINATION AND SO THAT EVERY ONE COULD GET WORLD CLASS EDUCATION.WHICH MAY ALSO INCREASE GLOBAL STANDARDS . SEE WE MUST ALSO CONSIDER THE PROBLEM OF THE DROPPERS REALITY: THERE ARE STUDENTS WHO ARE TRYING TO GET INTO IITs and NITs from the PAST 3-4 YEARS THIS MEANS THERE ARE STUDENTS WHO WANT JOIN COLLEGES ACCORDING TO THEIR CHOICES(MAINLY IITs AND NITs) AND SINCE IN ORDER TO MAXIMISE THE BENEFIT(FOR ALL KINDS OF THE STUDENTS TO PER
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Answer to a bigggggggg problemIt is kind of like two wrongs make a right. Let us say that x and y are both positive. Then the meaning of -(x) + (y) is just y - x and (y) - -(x) = y + x, subtracting a negative number is the same as adding the positive number. Now, let us say n is a positive integer. Then n * x can be thought of as adding x to itself n times which explains why a positive number times a negative number is always negative. So, what does -(n) * x? Well, multiplication is commutative, i.e., x * y = y * x. So -(n) * x = x * -(n) or -(n) * x = (-1 * n ) * x = ( n * -1 ) * x = n * ( -1 * x ) because
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