Hi nabarko,
Let length of rod be x.
let the other force be f .
So f - F=ma ------(1)
net torque about centre of rod is 0; so
F.x/2 = f . (x/2 - L)
F.x/2 = (F+ma) (x/2 - L) ---from (1)
After solving for x, we get x= { 2L(F+ma) } / ma
Hope that's ok.
Cheers.
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