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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: for those done with Calculus (atlest SL Loney)
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saket_brutus (112)

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Olaaa!! Perrrfect answer. 18  [29 rates]

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The integral can be written as :
  (1/2)*[  (x2+1) dx/(1+x4)   -   (x2-1) dx/(1+x4) ]
 
Call the first integral , I1 and the second integral I2
Divide by x(numerator and denominator) in both the integrals.
 
If u need help in proceeding, plz reply.
 
Cheers.

Saket
  this reply:   5 points  (with Olaaa!! Perrrfect answer.   in 1   votes   )     [?]
 
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