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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: AP GP HP is nt difficult
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CyBorG (1574)

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Olaaa!! Perrrfect answer. 252  [409 rates]

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 If A and G be the AM and GM between two numbers a,b then a,b are given by
A (A+G)(A-G)
 
If H is the HM between a and b then,
(H-2a)(H-2b)=H2
(1/(H-a))+(1/(H-b))=(1/a)+(1/b)
((H+a)/(H-a))+((H+b)/(H-b))=2
 
If a,b,c are any numbers then,
a3+b3+c3-3abc=(a+b+c)(a+bw+cw2)(a+bw2+cw)
where w is cube root of unity.

-ADARSH NITK Surathkal
  this reply:   52 points  (with 10  Olaaa!! Perrrfect answer.   in 11   votes   )     [?]
 
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