well the ans is 27/8.That is how it goes for solving first summation we goes from k=0 to infinity by that time 3i &3j remain constant so we can take them out as constant [i=0 ][ ][j=0 ][ ]1/3i.3j ( [k=0 ][ ]1/3k ) [i=0 ][ ][j=0 ][ ]1/3i.3j (3/2) Simmilarily we get 3/2 from all three
so ans is (3/2)3 =27/8
also 1/0 is not are u giving me a salute?
adversities cause some men to break other to break records............i m of the other type....... :-)
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