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Ask iit jee aieee pet cbse icse state board community Discussion Response Post to: Find value of k in the following question
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Deepak Aggarwal (3759)

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Olaaa!! Perrrfect answer. 709  [816 rates]

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1 + tan(44) = 1 + tan(45 - 1) = 1 + [ 1 - tan(1) / 1 + tan(1) ] = 2 / ( 1 + tan(1) )

do same for terms from end. See from above that denominator cancels out with ( 1 + tan1 ) in numerator. Like this all the terms cancel out giving the product equal to 222. So, k = 22.


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