1. 3BaCl2 + 2Na2PO4 ---> Ba3(PO4)2 + 6NaCl
1 mole 0.4 mole
here, Na2PO4 is the limiting reagent. So,
3BaCl2 + 2Na2PO4 ---> Ba3(PO4)2 + 6NaCl
0.6 mole 0.4 mole 0.2 mole
therefore, no. of moles of Ba3(PO4)2 is 0.2
2. 3MnO2 ----> Mn3O4 + O2
No. of Moles of MnO2 = 10/87
=> no. of moles on Mn3O4 = 10/261
Weight = molar mass * no. of moles = 229 *10/261 = 8.77g
3. No. of moles of Phosphorus = 3.1/31 = 0.1
in Ca2(PO4)2, for 2 moles of P, there are 3 moles of Ca.
thus, for 0.1 moles of P, there is (0.1*3/2) = 0.15 moles of Ca.
therefore, Weight of Ca = no. of moles * atomic wt = 0.15 * 60 = 6g