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19 Aug 2009 12:46:48 IST
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Please post the soln !!!!!!!! The sum of magnitudes of two forces acting at a point is 16N.If their resultant is normal to the smaller force and has a magnitude of 8n, the forces are?
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19 Aug 2009 13:00:14 IST
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...........
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All For That pink background behind my posts ;) |
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19 Aug 2009 13:07:44 IST
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. . . . . . . . .
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19 Aug 2009 13:16:09 IST
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19 Aug 2009 13:23:34 IST
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yaar cud someone explain the steps given below the diagram??
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19 Aug 2009 13:25:52 IST
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i have asked kjvenky to do so.just wait
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19 Aug 2009 13:26:10 IST
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what step you didnt understand?
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19 Aug 2009 13:28:04 IST
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just blow the diagram,,,,,,,,,,,,,,,,,,,,,,,,,,,,is sina= |B|/|A|
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19 Aug 2009 13:29:38 IST
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step 3
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19 Aug 2009 13:31:08 IST
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yes because B and Asina vector must cancel out as they resultant vector has magnitude in x direction
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19 Aug 2009 13:31:43 IST
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* sorry i mean C has no magnitude in x direction
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27 Aug 2009 13:47:18 IST
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let the 2 forces be x and y x+y=16-----(1), (x2+y2+2xycos@)1/2=8--------------(2) ysin@/x+ycos@=tan90=1/0 x=-ycos@-----------------(3) on solving the three equations 1,2,3 we get the forces x=6 and y=10.
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