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Reply Forum Index -> Trignometry originally posted here on IIT-JEE / AIEEE community   
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ankur khurana (527)

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Olaaa!! Perrrfect answer. 87  bad job dude!! I dont approve of this answer! 1  [135 rates]

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f and are two acute angles and then find

adversities cause some men to break other to break records............i m of the other type....... :-)
    
sreeraman nagasubramaniyan (3058)

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Olaaa!! Perrrfect answer. 538  [722 rates]

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[tex] \\ \\ \cos2\alpha = \frac{3\cos2\beta - 1}{3 - \cos2\beta} \\ \\ \frac{1-\tan^2\alpha}{1+\tan^2\alpha} = \frac{3\cos2\beta - 1}{3 - \cos2\beta} \\ \\ \frac{2}{-2\tan^2\alpha} = \frac{2\cos2\beta+2}{4\cos2\beta - 4} \\ \\ \frac{2}{\tan^2\alpha} = \frac{1+\cos2\beta}{1-\cos2\beta} \\ \\ \frac{\tan^2\alpha}{2} = \frac{\sin^2\beta}{\cos^2\beta} \\ \\ \tan\alpha = \sqrt{2}\tan\beta
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