Hot IASian
plzz ....prove that :rates assured
tan3A - tan4A - tanA = tan3A tan2A tanA
Blazing IASian
tan(3A) = tan(2A + A) =( tan(2A) + tan(A) ) / ( 1 - tan(2A) tan(A) )
tan(3A) - tan(A) tan(2A) tan(3A) = tan(2A) + tan(A)
tan(3A) - tan(2A) - tan(A) = tan(A) tan(2A) tan(3A)
I think there's some problem in the question. Its not 4A but 2A.