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Ask community Community Discussion Question: integ. x^5/(x^2+1)
Reply Forum Index -> Integral Calculus originally posted here on IIT-JEE / AIEEE community   
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[Post New] 13 Apr 2010 11:22:32 IST
   Subject: integ. x^5/(x^2+1)
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aman singh (0)

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integ. x^5/(x^2+1)
    
[Post New] 13 Apr 2010 21:48:52 IST
   Subject: integ. x^5/(x^2+1)
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Deepak Aggarwal (3759)

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I = int x5 . dx / x2 + 1

I = int (x2)2 x . dx / x2 + 1

Put y = x2 + 1

so, dy = 2x dx

or, x.dx = dy / 2

So, I = int (y - 1)2 . dy / 2y = int (y - 2 + y-1) . dy / 2

I = (1/2) ( (y2/2) - 2y + logy ) + C

I = (1/2) ( (x2 + 1)2/2) - 2(x2 + 1) + log(x2 + 1) ) + C

 
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