15 pC) but opposite sign are connected by a light, rigid, insulating rod of length d = 5.0 cm, as shown

above.  The charges are placed a distance r  = 10 cm away from a large conducting sheet carrying a uniform surface charge density σ = 800 nC/m2  (the sheet is oriented perpendicular to the page; the vertical line represents a cross section).

You can assume that the only forces acting in this problem are electrical (ignore gravitational effects). (a) Calculate the electric field due to the sheet of charge at the location of the dipole (you can use the

result we derived in class; no need to rederive using Gauss’s law).

(b) Sketch the electric field generated by the sheet in the figure above.

(c) Calculate the magnitude of the electric field due to the positive charge +q at the location of the negative charge –q.