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29 Sep 2010 13:35:05 IST
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Trace the curve: y^2(x^2-4)=x^4
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7 Oct 2010 14:01:55 IST
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y2(x2 - 4) = x4 or, y2 = x4 / (x2 - 4) or, y = + x2 / (x2 - 4)1/2 So, for the function to be defined, x2 - 4 > 0 or, x2 >4 or, x>2 and x<-2 Also, 
So, you can check in which interval the function increases and decreases. The graph would be this: 
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11 Nov 2010 21:29:46 IST
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Trace the curve: y^2(x^2-4)=x^4
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11 Nov 2010 22:53:17 IST
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no deepak u r wrong since at x=0 y =0...
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5 OUT OF 4 PEOPLE DO NOT UNDERSTAND A JOKE IN MATHS!!!!
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16 Nov 2010 18:30:36 IST
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hey i knw hw do trace this curve....deepak u r wrng...and the curve is a cusp passing through the origin, symmetric about x-axis and the x-axis is itself a tangent to the curve...
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26 Nov 2010 13:42:45 IST
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deepak is right i think........................ curve isn't defined until vaue of x>=4..........i totally agree with deepak
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16 Nov 2011 12:01:54 IST
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rite
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