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9 Jan 2007 15:02:33 IST
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Integrate wrt x 1) (sinx)/x and 2) (exponential) e to the power of -x square
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Hi Kab, I don't know if u know the answer or not( i have a funny feeling that u do know - hey; no offence  ). But the answer is that these 2 integrals cannot be found( assuming that the 2nd integral is e -x^2). Cheers.
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Saket |
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11 Jan 2007 16:56:43 IST
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You are right. Most probably they cannot be integrated.
But are you sure??????
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-ADARSH
NITK Surathkal
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11 Jan 2007 17:09:21 IST
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I am sure that this "CANNOT BE EVALUATED" .
The reason is, not every antiderivative f(x), even when it exists, is expressible in closed form in term of elementary functions such as polynomials, trigo, logarithmic or expo functions.
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11 Jan 2007 18:03:37 IST
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I also support the above!!!
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11 Jan 2007 18:12:51 IST
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thanx
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-ADARSH
NITK Surathkal
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11 Jan 2007 18:31:43 IST
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Hi Kab, I'm dead sure. Cheers.
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Saket |
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14 Jan 2007 21:38:31 IST
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HII KAB, WHEN U KNOW THAT UR QUESTION CAN'T BE EVALUATED THEN WHY U ASK THIS QUESTION?
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Manini Sahoo |
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15 Jan 2007 16:28:11 IST
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I wasnt sure that they couldnt be evaluated.
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-ADARSH
NITK Surathkal
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15 Jan 2007 21:57:01 IST
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any body can help me to solve this question
lim(1-cos 4x)/(1-cos 5x)
x->0
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Manini Sahoo |
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15 Jan 2007 22:00:59 IST
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one more doubt
lim{x(e pow2+x _e pow 2)}/(1-cos x)
x->0
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Manini Sahoo |
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15 Jan 2007 22:16:53 IST
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hello plz solve my problem
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Manini Sahoo |
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15 Jan 2007 22:27:31 IST
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Hi manini,
for ur first Q,
apply L'Hospital 's rule twice;
the ans is 16/25.
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15 Jan 2007 22:34:24 IST
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For ur 2nd Q,
take e^2 common; u'll be left with ... x(e^x-1)/(1-cosx)
{where ^ means power raised to)
apply L'Hospital 's rule twice again;
the ans is ..2e^2.
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16 Jan 2007 10:49:52 IST
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thank u
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Manini Sahoo |
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23 Jan 2007 15:27:56 IST
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We know sinx=x-x3/3!+x5/5!+......... (sinx)/x=1-x2/3!+x4/5!+.........  (sinx)dx/x= (1-x 2/3!+x 4/5!+........)dx =x-x3/(3)(3!)+x5/(5)(5!)+..........+c So I think its wrong to say(sinx)/x cannot be integrated but the answer is not a finite one.What do you people say?????
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-ADARSH
NITK Surathkal
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