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[Post New] 15 Jun 2009 09:36:13 IST
   Subject: lg(21+21i)
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vishvat (0)

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lg(21+21i)
    
[Post New] 15 Jun 2009 09:46:48 IST
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swapnil joshi (627)

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x=lg(21+21i)

10x=21+21i

x=log(21+21i)=1.4727342925659+0.3410940884605i       ans
winners dont do different things ,they do things differently
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[Post New] 15 Jun 2009 09:47:13 IST
   Subject: lg(21+21i)
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swapnil joshi (627)

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hey dude ,this is correct answer ,as I have calculated it using a computer program
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[Post New] 15 Jun 2009 13:43:43 IST
   Subject: lg(21+21i)
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Deepak Aggarwal (3759)

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log (21 + 21i) = log | 21 + 21i | + i arg (21 + 21i)

                         = log 21(2)1/2 + i (/4)
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[Post New] 15 Jun 2009 14:26:43 IST
   Subject: lg(21+21i)
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Decoder (1203)

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correct method is one by DEEPAK AGGARWAL..maths is nt using computer programs....such values r nt given in options... ;p ..............................log(21 +21i) = log(21) + 1/2.log2 + log(e^ipi/4) ..............or ....log (21) + 1/2.log(2) + i (pi/4)
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[Post New] 15 Jun 2009 17:47:23 IST
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edison (8935)

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ln (21 + 21i) = 3.3911 + 0.7854i
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