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α = log218 / log212 = 1 + 2log23 / 2 + log23β = log254 / log224 = 1 + 3log23 / 3 + log23You can now just assume that log23 = t,So, αβ + 5(α-β) = (1 + 2t / 2 + t) + (1 + 3t) / (3 + t) + 5 [ (1 + 2t / 2 + t) - (1 + 3t / 3 + t) = 1Hence, Proved.
α = log218 / log212 = 1 + 2log23 / 2 + log23
β = log254 / log224 = 1 + 3log23 / 3 + log23
You can now just assume that log23 = t,
So, αβ + 5(α-β) = (1 + 2t / 2 + t) + (1 + 3t) / (3 + t) + 5 [ (1 + 2t / 2 + t) - (1 + 3t / 3 + t) = 1
Hence, Proved.