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6 Jun 2009 11:27:10 IST
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Find the roots of e^ -1/z^2 e raise to power -1/z^2
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6 Jun 2009 11:41:39 IST
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question not clear. pls type again. is the ques. like this: roots of  alaso tell wheter z here is complex number or only a variable.
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OUR SUCCESS LIES IN OUR HAND.IT IS OUR WILL WHETER TO BELIEVE OR NOT BELIEVE THIS FACT. INFACT, OUR SUCESS AND FAILURE DEPENDS ON OUR ACTS AND DEEDS.
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6 Jun 2009 11:48:25 IST
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it is (e)-1/z^2 = 0  
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6 Jun 2009 11:48:41 IST
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it is (e)-1/z^2 = 0 yes, z is a complex number.
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6 Jun 2009 11:53:20 IST
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x=-1,y=0
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6 Jun 2009 12:07:57 IST
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how do u solve it?
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6 Jun 2009 12:28:36 IST
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(e)^-1/z^2 =e^-1-e^z^2=0 =>e^-1=e^z^2 =>taking log in both sides.. z^2=-1; let z=x+iy =>x+iy=i; x=0 and y=1
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11 Jun 2009 10:57:28 IST
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So, none could solve this. Answer to the question was no roots. Check it out now! HINT - USE LOG
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