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Ask community Community Discussion Question: a beaker contains water and benzene of ref. indices 4/3 and 3/2 respectively. If their de
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[Post New] 6 Feb 2012 20:24:07 IST
   Subject: a beaker contains water and benzene of ref. indices 4/3 and 3/2 respectively. If their de
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kavya bhat (5)

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how do i calculate that?
    
[Post New] 6 Feb 2012 20:30:52 IST
   Subject: a beaker contains water and benzene of ref. indices 4/3 and 3/2 respectively. If their de
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kavya bhat (5)

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*if their depths are 12 cm each, the apparent depth of the bottom of the container is?
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[Post New] 6 Feb 2012 22:44:16 IST
   Subject: a beaker contains water and benzene of ref. indices 4/3 and 3/2 respectively. If their de
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shivansh shrivastava (35)

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I gues,u shud add two seperate apparent depths,by findin with formula ref.index=real.d/apparent.d and puttin real.d=12cm. . .im n0t sure bou that formula
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[Post New] 7 Feb 2012 00:59:53 IST
   Subject: a beaker contains water and benzene of ref. indices 4/3 and 3/2 respectively. If their de
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Dipanshu Jaiswal (0)

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 app depth will be 3L/4 nd 2L/3 rispectively
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[Post New] 7 Feb 2012 17:11:11 IST
   Subject: a beaker contains water and benzene of ref. indices 4/3 and 3/2 respectively. If their de
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kavya bhat (5)

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i got the answer, u calculate the apparent depth of bottom using app depth= real depth/ ref. index , since water is denser and then calculate the depth of the benzene water interface using the same formula with ref. index of benzene. and then add the two, the answer comes to be 12/4/3=9 + 12/3/2=8 and so, 9+8= 17
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